Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World",
return 5.
1 public class Solution { 2 public int lengthOfLastWord(String s) { 3 if(0 == s.length()) 4 return 0; 5 s = s.trim(); 6 int count = 0; 7 8 for(int i = s.length() - 1; i >= 0;i--){ 9 if(‘ ‘ == s.charAt(i)){ 10 break; 11 } 12 count++; 13 } 14 return count; 15 } 16 }
原文：http://www.cnblogs.com/luckygxf/p/4090814.html