10 21 30 14 55 32 63 11 30 55 30
10 30 55 30 11 63 32 55 14 30 21 7 30 55 11 63 32 14 21
代码(好搓~~~啊~~~,凑和着看吧):
#include <iostream> #include <string> #include <cstdio> #include <string.h> #include <algorithm> #include <ctype.h> using namespace std; struct node { int data; struct node *next; }; struct node *nicreat(int n) //逆序创建链表 { int i; struct node *head, *p; head = new node; head->next = NULL; for(i=0; i<n; i++) { p=new node; cin>>p->data; p->next=head->next; head->next=p; } return head; } int main() { int n; cin>>n; int i, j; int len; struct node *head, *w, *q; struct node *h1, *p, *tail, *dd; head=nicreat(n); cout<<n<<endl; w=head->next; for(i=0; i<n; i++) { if(i==0) cout<<w->data; else cout<<" "<<w->data; w=w->next; } cout<<endl; //删除重复元素,重复的保留最前面的 h1=new node; h1->next=NULL; tail=h1; len=0; w=head->next; delete(head); for(i=0; i<n; i++) { if(h1->next==NULL) //此时链表为空 { p=new node; p->data = w->data; p->next=NULL; tail->next=p; tail=p; len++; q=w; w=w->next; delete(q); //将原链表的节点删除 } else //若不为空 { dd=h1->next; int ff=1; for(j=0; j<len; j++) //检查是否出现过 { if(dd->data == w->data ) { ff=0; break; } dd=dd->next; } if(ff==1 )//没出现过 { p=new node; p->data = w->data; p->next=NULL; tail->next=p; tail=p; len++; q=w; w=w->next; delete(q); } else if(ff==0 ) { w=w->next; } } //w=w->next; } cout<<len<<endl; w=h1->next; for(int k=0; k<len; k++) { if(k==0) cout<<w->data; else cout<<" "<<w->data; w=w->next; } cout<<endl; return 0; }
数据结构之 线性表---单链表的操作B(先逆序+再删除重复元素)
原文:http://www.cnblogs.com/yspworld/p/4094314.html