Binary String Matching

描述

Given two strings A and B, whose alphabet consist only ‘0’ and ‘1’. Your task is only to tell how many times does A appear as a substring of B? For example, the text string B is ‘1001110110’ while the pattern string A is ‘11’, you should output 3, because the pattern A appeared at the posit

输入

The first line consist only one integer N, indicates N cases follows. In each case, there are two lines, the first line gives the string A, length (A) <= 10, and the second line gives the string B, length (B) <= 1000. And it is guaranteed that B is always longer than A.

输出

For each case, output a single line consist a single integer, tells how many times do B appears as a substring of A.

样例输入

3

11

1001110110

101

110010010010001

1010

110100010101011 

样例输出

3

0

3 

 1 #include <stdio.h>
 2 #include <string.h>
 3 
 4 int main(){
 5     int T;
 6     char a[11];
 7     char temp[11];
 8     char b[1001];
 9     int a_length;
10     int b_length;
11     int i;
12     int amount;
13     
14     scanf("%d",&T);
15     
16     while(T--){
17         scanf("%s%s",a,b);
18         a_length=strlen(a);
19         b_length=strlen(b);
20         
21         amount=0;
22         for(i=0;i<b_length-a_length+1;i++){
23             memset(temp,0,11);
24             strncpy(temp,&b[i],a_length);
25             
26             if(strcmp(temp,a)==0){
27                 amount++;
28             }
29         }
30         printf("%d\n",amount);
31     }
32     return 0;
33 }

Binary String Matching

原文：http://www.cnblogs.com/zqxLonely/p/4095693.html