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LeetCode——Simplify Path

时间:2014-11-22 18:53:59      阅读:270      评论:0      收藏:0      [点我收藏+]

Given an absolute path for a file (Unix-style), simplify it.

For example,
path = "/home/", => "/home"
path = "/a/./b/../../c/", => "/c"

click to show corner cases.

Corner Cases:

  • Did you consider the case where path = "/../"?
    In this case, you should return "/".
  • Another corner case is the path might contain multiple slashes ‘/‘ together, such as "/home//foo/".

  • In this case, you should ignore redundant slashes and return "/home/foo".
原题链接:https://oj.leetcode.com/problems/simplify-path/
用一个栈来顺序存储比较方便。
public class SimplifyPath {
	public static void main(String[] args) {
		String ret = new SimplifyPath().simplifyPath("/a/./b/../../c/");
		System.out.println("result:"+ret);
	}
	public String simplifyPath(String path) {
		String[] params = path.split("/");
		Stack<String> stack = new Stack<String>();
		for(String param : params){
			if(param.equals(".."))
				stack.pop();
			else if(!param.equals("..") && !param.equals(".") && !param.equals(""))
				stack.push(param);
		}
		StringBuilder builder = new StringBuilder();
		for(String str :stack)
			builder.append("/"+str);
		return stack.isEmpty() ? "/":builder.toString();
	}
}

LeetCode——Simplify Path

原文:http://blog.csdn.net/laozhaokun/article/details/41317153

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