首页 > 其他 > 详细

Leetcode-Length of Last Word

时间:2014-11-29 08:22:21      阅读:249      评论:0      收藏:0      [点我收藏+]

Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,
Given s = "Hello World",
return 5.

Solution:

1 public class Solution {
2     public int lengthOfLastWord(String s) {
3         s = s.trim();
4         int index = s.length()-1;
5         while (index>=0 && s.charAt(index)!=‘ ‘) 
6             index--;
7         return (s.length()-index-1);        
8     }
9 }

 

Leetcode-Length of Last Word

原文:http://www.cnblogs.com/lishiblog/p/4129900.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!