2014.2.28 02:38
Implement strStr().
Returns a pointer to the first occurrence of needle in haystack, or null if needle is not part of haystack.
Solution1:
The first one is brute-force, reference is from source code of strstr() in <string.h>.
Total time complexity is O(n * m). Space complexity is O(1).
Accepted code:
1 // 1WA, 1AC, standard Brute-Force solution. 2 #include <cstring> 3 using namespace std; 4 5 class Solution { 6 public: 7 char *strStr(char *haystack, char *needle) { 8 const char *ptr = haystack; 9 size_t len = strlen(needle); 10 if (len == 0) { 11 return haystack; 12 } 13 while ((ptr = strchr(ptr, *needle)) != nullptr) { 14 if (strncmp(ptr, needle, len) == 0) { 15 return (char *)ptr; 16 } 17 ++ptr; 18 } 19 } 20 };
Solution2:
This solution uses KMP Algorithm, which runs in linear time.
The key difference between KMP and Brute-Force is the "next" array, that defines the position to backtrack when mismatch happens.
Here is the reference from Wikipedia of KMP Algorithm, if you‘d like to learn more about it.
Total time complexity is O(len(haystack) + len(needle)). Space complexity is O(needle).
Accepted code:
1 // 2CE, 1RE, 1WA, 1AC, KMP Algorithm 2 #include <cstring> 3 #include <vector> 4 using namespace std; 5 6 class Solution { 7 public: 8 char *strStr(char *haystack, char *needle) { 9 if (haystack == nullptr || needle == nullptr) { 10 return nullptr; 11 } 12 lp = strlen(needle); 13 lw = strlen(haystack); 14 15 if (lp == 0) { 16 return haystack; 17 } 18 19 if (lw < lp) { 20 return nullptr; 21 } 22 23 calculateNext(needle); 24 char *result = KMPMatch(haystack, needle); 25 next.clear(); 26 27 return result; 28 } 29 int lp; 30 private: 31 int lw; 32 vector<int> next; 33 34 void calculateNext(char *pat) { 35 int i = 0; 36 int j = -1; 37 38 next.resize(lp + 1); 39 next[0] = -1; 40 while (i < lp) { 41 if (j == -1 || pat[i] == pat[j]) { 42 ++i; 43 ++j; 44 next[i] = j; 45 } else { 46 j = next[j]; 47 } 48 } 49 } 50 51 char* KMPMatch(char *word, char *pat) 52 { 53 int index; 54 int pos; 55 56 index = pos = 0; 57 while (index < lw) { 58 if (pos == -1 || word[index] == pat[pos]) { 59 ++index; 60 ++pos; 61 } else { 62 pos = next[pos]; 63 } 64 65 if (pos == lp) { 66 // the first match is found 67 return word + (index - lp); 68 } 69 } 70 71 return nullptr; 72 } 73 };
LeetCode - Implement strStr(),布布扣,bubuko.com
原文：http://www.cnblogs.com/zhuli19901106/p/3572745.html