原文:
Write a method to replace all spaces in a string with ‘%20’.
译文:
写一个函数,把字符串中所有的空格替换为%20 。
先计算出空格个数,然后从后往前逐个替换空格,不用新开数组
package Arrays_Strings; import CtCILibrary.AssortedMethods; public class S1_4 { // 先计算出空格个数,然后从后往前逐个替换空格 public static void replaceSpaces(char[] str, int length) { int spaceCount = 0; for(int i=0; i<length; i++) { // 计算空格个数 if(str[i] == ‘ ‘) { spaceCount++; } } int end = length - spaceCount + 3*spaceCount; // 占一个位置的空格换成占3个位置的%20 int pos = end-1; for(int i=length-1; i>=0; i--) { if(str[i] == ‘ ‘) { str[pos] = ‘0‘; str[pos-1] = ‘2‘; str[pos-2] = ‘%‘; pos -= 3; } else{ str[pos] = str[i]; pos--; } } } public static void main(String[] args) { String str = "a s d"; char[] arr = new char[3*str.length()]; for (int i = 0; i < str.length(); i++) { arr[i] = str.charAt(i); } replaceSpaces(arr, str.length()); System.out.println("\"" + AssortedMethods.charArrayToString(arr) + "\""); } }
Arrays_Strings 把字符串中所有的空格替换为%20 @CareerCup,布布扣,bubuko.com
Arrays_Strings 把字符串中所有的空格替换为%20 @CareerCup
原文:http://blog.csdn.net/fightforyourdream/article/details/20094727