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hdoj1012--u Calculate e

时间:2014-03-01 00:33:32      阅读:528      评论:0      收藏:0      [点我收藏+]
Problem Description
A simple mathematical formula for e is

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where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
 
Output
Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.
Sample Output
n e
- -----------
0 1
1 2
2 2.5
3 2.666666667
4 2.708333333
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#include<iostream>
#include <iomanip>

using namespace std;

int main()
{
    int i,n;
    double s,t;
    cout<<"n e"<<endl;
    cout<<"- -----------"<<endl;
    cout<<"0 1"<<endl;
    cout<<"1 2"<<endl;
    cout<<"2 2.5"<<endl;
    s=2.5;
    n=2;
    for(i=3; i<=9; i++)
    {
        n=i*n;
        s+=1.0/n;
        cout<<i<<" "<<fixed<<setprecision(9)<<s<<endl;
    }
    return 0;
}
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hdoj1012--u Calculate e

原文:http://www.cnblogs.com/xueda120/p/3573232.html

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