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LeetCode刷题之三:判断两个二叉树是否相同

时间:2014-12-12 23:36:45      阅读:532      评论:0      收藏:0      [点我收藏+]

题目为:

Given two binary trees, write a function to check if they are equal or not.

Two binary trees are considered equal if they are structurally identical and the nodes have the same value.

解题思路:这种题目也是递归操作简单

代码为:

/**
 * Definition for binary tree
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
public class Solution {
    public boolean isSameTree(TreeNode p, TreeNode q) {
        boolean flag = false;
        if(p==null && q == null)
            return true;
        if(p == null && q!= null)
            return false;
        if(p!= null && q== null)
            return false;
        if(p.val != q.val)
            return false;
        return isSameTree(p.left,q.left)&&isSameTree(p.right,q.right);
        
    }
}


LeetCode刷题之三:判断两个二叉树是否相同

原文:http://blog.csdn.net/longshengguoji/article/details/41901877

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