C++ 通过引用来传递和返回对象

提高效率

#include<iostream>
using namespace std;
class C{
public:
	void set(int n){num=n;}
	int get() const {return num;}
private:
	int num;
};

void f(C& );
C& g();

int main()
{
	C c1, c2;
	f(c1);
	c2=g();
	cout<<c2.get()<<endl;
	cout<<"***************"<<endl;
	cout<<c1.get()<<endl<<c2.get()<<endl;
	return 0;
}

void f(C& c){
	c.set(-999);
	cout<<c.get()<<endl;
}

C& g(){
	static C c3;
	c3.set(123);
	return c3;
}

C++ 通过引用来传递和返回对象,布布扣,bubuko.com

C++ 通过引用来传递和返回对象

原文：http://blog.csdn.net/slience_perseverance/article/details/20134981