LeetCode: Path Sum 解题报告

Path Sum

Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.

For example:
Given the below binary tree and sum = 22,
              5
             / \
            4   8
           /   / \
          11  13  4
         /  \      \
        7    2      1
return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.

SOLUTION 1:

相当简单的题目，用递归解决。base case: 如果root是叶子，并且sum为root的值，返回true.
否则在左右分别 找一下就好（调用递归），任何一边返回true都可以的。

https://github.com/yuzhangcmu/LeetCode_algorithm/blob/master/tree/hasPathSum.java

 1 public boolean hasPathSum(TreeNode root, int sum) {
 2         if (root == null) {
 3             return false;
 4         }
 5 
 6         if (root.left == null && root.right == null && sum == root.val) {
 7             return true;
 8         }
 9 
10         return hasPathSum(root.left, sum - root.val)
11                 || hasPathSum(root.right, sum - root.val);
12     }

View Code

LeetCode: Path Sum 解题报告

原文：http://www.cnblogs.com/yuzhangcmu/p/4172695.html