LeetCode: Best Time to Buy and Sell Stock II 解题报告

Best Time to Buy and Sell Stock II
Question Solution
Say you have an array for which the ith element is the price of a given stock on day i.

Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy one and sell one share of the stock multiple times). However, you may not engage in multiple transactions at the same time (ie, you must sell the stock before you buy again).

解：
既然要最大化利润，我们应该拿下股票所有的升值部分。从开始到最后股票可能有升有降，那么，我们把每一个升值的区间的利润加在一起就是最大值。

也就是每次比较当天和前一天的股票值，如果是上升，就加上这个差值即可。

 1 public class Solution {
 2     public int maxProfit(int[] prices) {
 3         if (prices == null) {
 4             return 0;
 5         }
 6         
 7         int maxProfit = 0;
 8         
 9         int len = prices.length;
10         for (int i = 1; i < len; i++) {
11             int dif = prices[i] - prices[i - 1];
12             
13             if (dif > 0) {
14                 maxProfit += dif;
15             }
16         }
17         
18         return maxProfit;
19     }
20 }

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GitHub代码链接

LeetCode: Best Time to Buy and Sell Stock II 解题报告

原文：http://www.cnblogs.com/yuzhangcmu/p/4199816.html