Suppose a sorted array is rotated at some pivot unknown to you beforehand.
(i.e., 0 1 2 4 5 6 7 might become 4
5 6 7 0 1 2).
Find the minimum element.
You may assume no duplicate exists in the array.
二分法· 注意left和right的选择
public class Solution {
public int findMin(int[] num) {
assert num.length>0;
int left = 0,right = num.length-1;
while(left<right){
if(num[left]<num[right]) return num[left];
int mid = (left+right)/2;
if(num[mid]>num[right]){
if(mid==left) left = mid++;
left = mid;
}else{
right = mid;
}
}
return num[left];
}
}
[LeetCode]Find Minimum in Rotated Sorted Array
原文:http://blog.csdn.net/guorudi/article/details/42395439