A robot is located at the top-left corner of a m x n grid (marked ‘Start‘ in the diagram below).
The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked ‘Finish‘ in the diagram below).
How many possible unique paths are there?
Above is a 3 x 7 grid. How many possible unique paths are there?
解题报告:动态规划的基础题,用一个数组存储到各个点的有多少条路。
如果数组没被存入数字,那就存储,这条路前一点的数字。如果已被存入数字,那就加入这条路前一点的数字。
class Solution { public: int uniquePaths(int m, int n) { int temp[m][n]; for (size_t i = 0; i != m; i++) for(size_t j = 0; j != n; j++) temp[i][j] = -1; temp[0][0] = 1; for (size_t i = 0; i != m; i++) { for(size_t j = 0; j != n; j++) { if(j != n-1) { if(temp[i][j+1] != -1) temp[i][j+1] += temp[i][j]; else temp[i][j+1] = temp[i][j]; } if(i != m-1) { if(temp[i+1][j] != -1) temp[i+1][j] += temp[i][j]; else temp[i+1][j] = temp[i][j] ; } } } return temp[m-1][n-1]; } };
Note: m and n will be at most 100.
原文:http://blog.csdn.net/vanish_dust/article/details/42748737