javascript 数组去重 unique

 1 Array.prototype.unique = function (isStrict) {
 2     if (this.length < 2)
 3         return [this[0]] || [];
 4     var tempObj = {}, newArr = [];
 5     for (var i = 0; i < this.length; i++) {
 6         var v = this[i];
 7         var condition = isStrict ? (typeof tempObj[v] != typeof v) : false;
 8         if ((typeof tempObj[v] == "undefined") || condition) {
 9             tempObj[v] = v;
10             newArr.push(v);
11         }
12     }
13     return newArr;
14 }

验证：
var arr = ["9", 9, 1, 3, 8, 7, 7, 6, 6, 5, 7, 8, 8, 7, 4, 3, 1, 22, 22, ‘a‘, ‘a‘,‘bcd‘, ‘abc‘, ‘bcd‘];
var newArr = arr.unique(true);
alert(newArr.join(","));//严格模式:9,9,1,3,8,7,6,5,4,22,a,bcd,abc，将其中"9",9认为不同

var newArr = arr.unique();
alert(newArr.join(","));//普通模式:9,1,3,8,7,6,5,4,22,a,bcd,abc，将其中"9",9认为相同