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uva 705

时间:2015-01-18 22:39:34      阅读:384      评论:0      收藏:0      [点我收藏+]

题意,给你迷宫算出其中个封闭空间的个数,以及求出所有封闭的空间的最大步长,但是给你的迷宫式“/”,“\”来标记的所以需要将每个格子分开来3*3的格子来算,

一开始按照2*2来算,2*2有临界情况不好算(233333)……

格式需要额外空一行……

题很简单,就是dfs走出边界说明不是封闭的……

不过就这样了……还是太弱了……

话说,今天又颓了一天……

233333333

代码……

技术分享
#include <iostream>
#include <cstdio>
#include <cmath>
#include <cstring>
#include <algorithm>
#include <cstdlib>
#include <stack>
#include <cctype>
#include <string>
#include <malloc.h>
#include <queue>
#include <map>

using namespace std;
const int INF = 0xffffff;
const double Pi = 4 * atan(1);
const int Maxn = 200 + 10;
//int dir2[8][2] = {{-1,0},{0,-1},{-1,1},{1,-1},{-1,-1},{1,0},{0,1},{1,1}};
int dr[] = {1,0,-1,0,-1,1,-1,1};
int dc[] = {0,1,0,-1,1,-1,-1,1};

bool graph[300][300];
int w,h;
int num;
bool flag;

void dfs(int r,int c){
    if(r < 0 || c < 0 || r > 3*h-1 || c > 3*w-1 ){
        flag = 1;
        return;
    }
    if(graph[r][c])
        return;
    graph[r][c] = 1;
    num++;
    for(int i = 0;i < 4;i++){
        int xx = r + dr[i];
        int yy = c + dc[i];
        dfs(xx,yy);
    }
}

int main()
{
#ifndef ONLINE_JUDGE
    freopen("inpt.txt","r",stdin);
#endif
    int cas = 0;
    while(cin >> w >> h){
        if(!w && !h)
            break;
        cout << "Maze #" << ++cas << ":" << endl;
        if(!w || !h){
            cout << "There are no cycles." << endl << endl;
            continue;
        }
        char str[100];
        memset(graph,0,sizeof(graph));
        for(int i = 0;i < h;i++){
            cin >> str;
            for(int j = 0;j < w;j++){
                if(str[j] == \\){
                    graph[3*i][j*3] = graph[3*i+1][3*j+1] = graph[3*i+2][3*j+2] = 1;
                }
                else if(str[j] == /){
                    graph[3*i][j*3+2] = graph[3*i+1][3*j+1] = graph[3*i+2][3*j] = 1;
                }
            }
        }
     /*   for(int i = 0;i < 3*h ;i++){
            for(int j = 0;j < 3*w;j++)
                cout << graph[i][j];
            cout << endl;
        }*/
        int cnt = 0;
        int road = -1;
        for(int i = 0;i < 3*h;i++){
            for(int j = 0;j < 3 * w;j++){
                if(!graph[i][j]){
                    flag = 0;
                    num = 0;
                    dfs(i,j);
                    if(flag)
                        continue;
                    cnt++;
                    if(num > road)
                        road = num;
                }
            }
        }
        if(cnt == 0)
            cout << "There are no cycles." << endl;
        else{
            cout << cnt << " Cycles; the longest has length " << road/3 << "." << endl;
        }
        cout << endl;
    }
    return 0;
}
View Code

测试用例:

技术分享
6 4 
\//\\/ 
\///\/ 
//\\/\ 
\/\/// 
3 3 
/// 
\// 
\\\ 
5 5 
/\/\/ 
\/\/\ 
/\/\/ 
/\/\/ 
\/\/\ 
4 4 
//\\ 
//\\ 
\\// 
\\// 
6 6 
/\/\/\ 
\//\\/ 
///\\\ 
\\\/// 
/\\//\ 
\/\/\/ 
6 4 
/\/\/\ 
\\/\// 
//\/\\ 
\/\/\/ 
6 4 
/\/\/\ 
\\/\// 
//\/\/ 
\/\/\/ 
0 1 

1 0 
75 75 
\\\//\/\\/////\//\\\\\\/\//\\\\//\//////\\\/\//\/\\/\\/\/\//\/\/\\\/\/\

\//\ 
//\\\/\/\\\//\/\\\/\/\/\\\/\/\/\\//\/\\\/\\/\/\//\\/\///////\//\/\\///\/

\\/ 
/\\//\///\\\\/////\//\/\///\\\\/\//\/\\/\\\\\\/\////\\\\//\\////\/\\\/\/

\\\ 
\\\//\\\/\\/\/\/\\/\/\\\\/\\\\//\\\/\/\\/\\\\\\\\/\\/\////\\//\\\//\/

\///\\ 
/\\//\/\/\/\\\//\/\/\\/\\/\\\\\//\\/\\///\\/\\\///\\//\\///\//////\\//\/

\\/ 
\\\\\//\\\\/\\/\///\\/\/\\/\///\////\/\\\/\\/\/\/\\\/\\\\/////\\\\//\\\

\//\ 
\///\/\/\\//\\\\/\\\\//\/\//\\/\///\\\\\\\/\\\\/\/\\\//\\/\\//\///\/\\

\//\/ 
\\/\\//////\//\\/\/\\\\\\//\\\\//\//\//\/\/\/\/\\//\\/\///\//\\\\\/\\//\

\\\ 
//\\/\//\\//\//\//\/\\///\\/\/\////\\/\\///\////\/\\///\\/\///\\\\//\\/

\/// 
\//\////\///\\\\\\\///\//\/\///\\/\/\\\\///\\\/\\\///\\\/\\//\\/\\/\//\/

\\\ 
/\\//\\///\\\\\\///\////\///\/\/\\\//\\/\\/\////\/\\/\/\////\/\/\\/\/\/

\/\/ 
/\/\\\\\/\\/\/\\/\\///\\//\//\/\//\//\////////\////\\/\\\\\\\///\\////\

\/\\ 
/\//\\/\\\/\\/\//\\\\\/\\\////\//\\/\\\\\\\/////\\\////\/\\//\/\\\\\/\//

\\\ 
\/\\/\//\\\//\/\\\/\\///\\\\\\\\/\\\//\\\///\\\/\\\/\\\\\\/\/\\/\/\/\/\/

\/\ 
//\\//\\/\\//\\\\///\\\\\\\/\\///\\//\///\//////\/\//\/\\\\/\\/\//\\/\/

\/// 
\\/\/\//\/\//\\///\\\\\/\///////////\///\\/\/\//\/\///\/\\\/\/\\/\\\\\/\

\/\ 
///\\\\///\/\//\\\\\/\/\\\\///\\\/\\\\\\\\\\///\\\\\/\///\\/\/\///\\\\\

\/\/ 
\//\\\\\/\////\\\/\\\/\\\\/\/\//\////\\//\//////\/\//\\/\///\/\/\\///\

\///\ 
/\\/\\\\\\\\\\\\//\\\///\///\\/\\\\///\////\\///\//\/////\\\//\//\\/\\\/

\\/ 
//\/////\\/\\\\/\\\/\\//\\\\\//////\//\\/\////\///\\\\//\////\/\/\/\///

\//\ 
//\\\\\/\//\//\\\\\\///\\\/\/\////\/\/\\\\\/\///\/\\\///\\//\\\/\/\\//\/

\/\ 
\\/\\\/\\//\///\\//\\\\\\/\/\\///////\/\//\\\/\\////\\\\\/\\\/\\/\/\////

\\\ 
/\\//\\\\/\/\/\\/\\/\/\\///\////\\\//\/\\//\\/\///\/\\//\\/\////\//\\/\\

\\\ 
\\/\//\\///\/\/\//\//\\\\\//\/\\/\/\//\\///////////////\/\\/\\\/\\\\/\\/

\// 
//\//\////\///\/\/\/\///\\//\\/\\//\//\\/\//\/\/\//\\\\\\///\/\\\\\\//\/

\\/ 
\\//\//\\//\\/\\\\/\\\\\/\\/\\//\/\\\/\//\\\///\\/\\\/\\//\\/\\/\///\/\\

\/\ 
/\//\//\/\\\/\\///\\\/\\/\/\\///\\\\///\//\/\\\\///\\\\/\\/\\\/\///\/\\

\//\ 
\//\\//\///\/\/\\\\/\\/\\\\\\////\\\\/\\\///\\/\\/\\\\\\/\//\\/\\//\/\//

\// 
//\\\/\///\/\\\\\/\\//\////\\//\\//\/\//\\/////\\\/\\\/////\\//\/\/\\\/\

\\/ 
//\/\\/////\\\\\\////\\\\/\\/\//\/\\//\\\//\/\///\\/\\\\//\///\//\///\/\

\\/ 
//////\/\///\\\///////\\\/\/\\//\\\//\\\\\\/////\//\/\/////\\//\\/\/\/\/

\/\ 
/\/\///\\//\///\\\\\/\\/\\////\/\/\/\//\//\\///\///\\/\/\/\/\\\\//\/\\

\//\\ 
\\/\/\//\\\//\\//\///\\\/\\//\///\/\////\/\/\\\/\//\\\///\/\/\\/\///\\

\///\ 
\//\//\\/\///\/\/\\/\/\\\\///\\/////\/\\///////////\/\\\\/\\\\\/\/////

\///\ 
/\///\\\////\\\\/\/\\\///\//\\\\\\/\///\\//\//////\\/\\/\\\/\\\\\\/\//\

\/// 
\/\////\/\///\\///\///\\\/\\\/\/\\/\/\\\\/\\\\/////\\\\////\///\\\/\///\

\// 
/\\//////\/\////\/\///\\\/\///\\\\//////\\/////\/\////\\/\/////\\//\//\

\/\\ 
/\/\/\\///\\\\///\\//\/\/\/\////\//\//\\/\//\//\/\////\/\////\\/\//\\\\

\/\\ 
/\\\\\/\/\/\/\\\/\\\//\\/\\/////\/\/\\//\\/\/\//\/\/\\////\//\//\/\\/\\

\/\\ 
\\/\\\/\/\\\/\\\////////\\//\\/\///\/\/\////\//\\/\\\\\\\\//\\\\/\\\\\\/

\// 
//\/\/\//\/\/\/\\/\/\\/\\\/\//\//////\//\\\\\\\///\\/\//////\\/\\////\\\

\/\ 
////\/\\/\\///\\\\///\/\//\\/\/\//\\/\//\/\\/\//////\//\/////\/\\\/\\/\

\/\\ 
//\/\//\\/\//\/\\\\//\\//\/\//\\\///\//\\\///\\\\/\\//\\\\//\//\\\\/\\/\

\/\ 
/\\\\////\\//\\\/\\\\\///\\\\\/\\\\\///\\\/\//\\\\//\\/\///////\/\//\

\///// 
//\\\\\\/\/\\/\\\/\/\\\\//\//\\/\\\\/\/\\\/\//\/\/\/\\\////\/\\///\/\/

\//\\ 
///\/\///\\/\\/\/\/\///\//\///\////\\//\\/\/\//\\\////\////\////\\\\/\

\///\ 
\\\//\//\\\\\//\//\\////\//\\///\/\/\\\/\//\/\\\//\\\/\\\\//\\/\//\//

\///// 
\/\\\\\\\\\/\//\\\/\\\\\/\\\/\\/\/\/\/\/\\\\/////\//\\\/\\\\\\/\\/\\\\\

\/\/ 
//\/////\/\/\\///////\\//\\\\\\////\\////\/\//\///\\\\//\/\\\\\\\//\/\\\

\// 
\\/\/\\\//\//\\\//\/\\\\/\\/\\///////\///\\/\\\/\///\\///////\\\/\\\\\\\

\// 
\\//\/\//\\//\\//\\\\\\/\\\/\/\\/\\\\\//\\\\/\/\//\//\///\\\\/\\//\////\

\\/ 
/\\/\/\//\//\\\/\//\\/\/\\\\\\/\\//\/\\/\\///\/\\\//\\//\\/\\\\////\//\

\/// 
///\\\\/\/\\\\/\\///\\\//\/\//\//\\\//\\///\////\/\//\\\///\//////\\\\\/

\\\ 
/\\\/\////\///\\\\///\\\\/\/\\\\\/\//\\/\\//////\\\\\/\\/\//\///\\/\\\/\

\\/ 
\\\//\\\\\\/\\\//\\//\//\/\\//\\\////\\/\/\/\\/\\\///\///\/\\/\\\/\/\//

\//\ 
\/\\\/////\\////\////\\\//\\/\\/\/\\\/\/\/\/\/\///\////\\\///\\//\/\/\//

\\/ 
//\/\///\\//\/\\////\///\\/\////\/\///\\\//\//////\\\\\/\\/\\\/\\/\\\\\/

\// 
//\/\//\\/\///\\/\\///\///\//\/\\//////\//\\\\/\///////\\\////\\/\//\//

\//\ 
//\\\/\\/\/\/\\/\/\/\//\\\/\//\//\\\\/\//\\\\\\/\////\\\/\\\/\\//\//\/\\

\// 
\/\\/\\\\/\//\/\\/\/\\\//\\\\/\//\\/\/\\\\\///\\\\\/\\\/\/\\/\\\\\\/\/\/

\/\ 
\\///\/\/\///\/\\\\\/\\/\//////\/\///\/\/\\/\/\\//\/\//\//\\\\/\\\\///\/

\/\ 
/\/\/\\\\/\///\\/\/\\/\/\\\\/\/\/\//\\\\\/////\//\\//\\/\\\///\\\//\\\/\

\\\ 
/\\\\//\///\//\/////\/\\/////\/\/\\\\/\\//\//\\\\\/\////\\\\/\\/\////\\

\//\ 
\/\/\///\//\\\\\/\\\\\///\//\\////\\\\\/\/////\\\/\\//\\\///\///\//\///\

\\/ 
\///\\\////\/\\/\/\\//\/\////\\\\/\\\/\\/\\\\\\\//\\////\/\\\\\\///\//\/

\// 
/\/\//\///\//////\\\/\\/\///\/\/\//\\/\/\\////\\\\\\/\/\\\//\/\\/\\\/\//

\\\ 
/\\//\\\//////\\/\\///\/\/\\/\/\////\\/\\\/\\//////////\///\/\\/\\\/\\\

\/\/ 
///\//\/\\//\/\//\//\///////\\\//\\\\//\/\/\\//\\/\//////\\\\\\\///\/\\/

\// 
\\///\/\\\/\//\///\\\\\\/\\\\/\\/\\//\/\\\/\\\/\/\//\///\\///\/\///\////

\/\ 
\////\\////\\/\\\/\/\///\///\//\/\/\\/\/\/\\\///\\\\\///\/\\\/\\/\/\\\/

\//\ 
\\\/\/\\////\\///\//\\\\/\/\\\//\//\////\/\//\/\\\\\/\//\/\//////\\/\\//

\\\ 
\////\\\/////\\\//\\\\//\\\\//\\/\\\\//\/\/\\\\/\///\//\\//\\\\//\/

\//////\ 
\\\\\//\\\/\\/\////\\//\\//\/\/\/\/////\\/\\//\///\\/\//\\\\\\\///\/\//

\/\\ 
/\/\\//\//\/\\\/////\\\/\\\//\//\////\\///\/\//\\\\\/\/\//////\\/\\/\\/

\/// 
\/\//\//\//\\///\\\//\\////////\\\\//\//\//\\\/\\///\/\/\/\///\/\////\/\

\\/ 
5 5 
//\\\ 
///\\ 
\\\\\ 
/\\// 
\\\// 
0 0 
View Code

ans:

Maze #1: 
2 Cycles; the longest has length 16. 

Maze #2: 
There are no cycles. 

Maze #3: 
6 Cycles; the longest has length 4. 

Maze #4: 
2 Cycles; the longest has length 12. 

Maze #5: 
7 Cycles; the longest has length 20. 

Maze #6: 
2 Cycles; the longest has length 28. 

Maze #7: 
1 Cycles; the longest has length 4. 

Maze #8: 
There are no cycles. 

Maze #9: 
There are no cycles. 

Maze #10: 
586 Cycles; the longest has length 1128. 

Maze #11: 
1 Cycles; the longest has length 24. 

 

uva 705

原文:http://www.cnblogs.com/hanbinggan/p/4232447.html

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