/* *+ ------------------------------- * 计算当天起始点和结束点时间戳 去当天的数据 *+ ------------------------------ */ $daybegin=strtotime(date("Ymd")); $dayend=$begin+86400; $query = "SELECT * FROM `info` WHERE addtime<$dayend AND addtime>$daybegin";
原文：http://www.cnblogs.com/bwzhangtao/p/4233447.html