PAT 1061. Dating

题目：http://pat.zju.edu.cn/contests/pat-a-practise/1061

思路：字符处理。题意不清，没啥意思。

代码：

#include<cstdio>
#include<cstring> 
#include<algorithm>
using namespace std;
int main()
{
	char s1[65],s2[65],s3[65],s4[65];
	int i;
	gets(s1);
	gets(s2);
	gets(s3);
	gets(s4);
	for(i=0;s1[i]!=‘\0‘&&s2[i]!=‘\0‘;i++)
		if((s1[i]>=‘A‘&&s1[i]<=‘G‘)&&(s1[i]==s2[i]))
		{
		        int tmp=(s1[i]-‘A‘)+1;
			if(tmp==1) printf("MON ");
			else if(tmp==2) printf("TUE ");
			else if(tmp==3) printf("WED ");
			else if(tmp==4) printf("THU ");
			else if(tmp==5) printf("FRI ");
			else if(tmp==6) printf("SAT ");
			else  printf("SUN ");
			break;
		}
	 for(i++;s1[i]!=‘\0‘&&s2[i]!=‘\0‘;i++)
		if(s1[i]==s2[i])
		{
		   if(s1[i]>=‘0‘&&s1[i]<=‘9‘){ printf("0%c:",s1[i]);break;}
		   else if(s1[i]>=‘A‘&&s1[i]<=‘N‘)
		   {
			  printf("%d:",s1[i]-‘A‘+10);
		          break;
		   }
		}
	
	for(i=0;s3[i]!=‘\0‘&&s4[i]!=‘\0‘;i++)
		if((s3[i]==s4[i])&&(s3[i]>=‘a‘&&s3[i]<=‘z‘||s3[i]>=‘A‘&&s3[i]<=‘Z‘))
		{
		   if(i<10)  printf("0%d\n",i);
		   else printf("%d\n",i);
		   break;
		}
	return 0;
}

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PAT 1061. Dating

原文：http://blog.csdn.net/zqh_1991/article/details/20473201