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[LeetCode] Longest Substring Without Repeating Characters

时间:2015-01-23 18:09:14      阅读:235      评论:0      收藏:0      [点我收藏+]

 

Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters for "abcabcbb" is "abc", which the length is 3. For "bbbbb" the longest substring is "b", with the length of 1.

 

http://blog.csdn.net/pickless/article/details/9018575

#if 0
class Solution {
public:
    int lengthOfLongestSubstring(string s) {
        // Start typing your C/C++ solution below
        // DO NOT write int main() function
        int locs[256];//保存字符上一次出现的位置
        memset(locs, -1, sizeof(locs));

        int idx = -1, max = 0;//idx为当前子串的开始位置-1
        for (int i = 0; i < s.size(); i++)
        {
            if (locs[s[i]] > idx)//如果当前字符出现过,那么当前子串的起始位置为这个字符上一次出现的位置+1
            {
                idx = locs[s[i]];
            }

            if (i - idx > max)
            {
                max = i - idx;
            }

            locs[s[i]] = i;
        }
        return max;
    }
};
#endif
class Solution 
{
    public:   
        int lengthOfLongestSubstring(string s)  
        {   
            int hash[256]; // save the index of s[i]
            int  start = -1; 
            int len = 0;

            memset(hash, -1, sizeof(hash));

            for(int i = 0; i< s.size(); i++/**/)
            {   
                // update the start if the start is in the front of the old hash[s[i]]
                if(start < hash[s[i]])
                    start = hash[s[i]];
                len = max(i - start, len);
                hash[s[i]] = i;
            }   

            return len;
        }   
};

 

[LeetCode] Longest Substring Without Repeating Characters

原文:http://www.cnblogs.com/diegodu/p/4244521.html

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