水题
Description
Input
Output
Sample Input
Sample Output
1 #include<cstdio> 2 #include<iostream> 3 #include<cstring> 4 #include<cmath> 5 using namespace std; 6 7 int main() 8 { 9 int n; 10 while (cin>>n&&n&&n<100) 11 { 12 int T[10005]; 13 int i; 14 for (i = 0; i<n; i++) 15 { 16 cin >> T[i]; 17 if (T[i] >= 100) return 0; 18 } 19 int sum; 20 sum = T[0] * 6 + 5; 21 for (i = 0; i<n - 1; i++) 22 { 23 if (T[i + 1]>T[i]) sum += (T[i + 1] - T[i]) * 6 + 5; 24 if (T[i + 1]<T[i]) sum += (T[i] - T[i + 1]) * 4 + 5; 25 if (T[i + 1] == T[i]) sum += 5; 26 } 27 cout << sum << endl; 28 } 29 return 0; 30 }
原文:http://www.cnblogs.com/yifangfengjing/p/4252497.html