Find the contiguous subarray within an array (containing at least one number) which has the largest sum.
For example, given the array [?2,1,?3,4,?1,2,1,?5,4]
,
the contiguous subarray [4,?1,2,1]
has the largest sum = 6
.
If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.
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/********************************* * 日期:2015-01-27 * 作者:SJF0115 * 题目: 53.Maximum Subarray * 网址:https://oj.leetcode.com/problems/maximum-subarray/ * 结果:AC * 来源:LeetCode * 博客: **********************************/ #include <iostream> #include <climits> using namespace std; class Solution { public: int maxSubArray(int A[], int n) { if(n <= 0){ return 0; }//if // 最大和 int max = A[0]; // 当前最大和 int cur = 0; for(int i = 0;i < n;++i){ // 一旦当前最大和小于0就重置为0,一个负数只能使最大和变小 if(cur < 0){ cur = 0; }//if cur += A[i]; if(cur > max){ max = cur; }//if }//for return max; } }; int main(){ Solution solution; int n = 9; int A[] = {-2,1,-3,4,-1,2,1,-5,4}; int result = solution.maxSubArray(A,n); // 输出 cout<<result<<endl; return 0; }
原文:http://blog.csdn.net/sunnyyoona/article/details/43200983