62. Unique Path Leetcode Python

Above is a 3 x 7 grid. How many possible unique paths are there?

这题有两种解法

1.直接的数学表达式  choose m-1 from m+n-2

class Solution:
    # @return an integer
    def fac(self,n):
        if n==1 or n==0:
            return 1
        return n*self.fac(n-1)
    def uniquePaths(self, m, n):
        if m==1 or n==1:
            return 1
        val1=self.fac(m+n-2)
        val2=self.fac(m-1)
        val3=self.fac(n-1)
        result=val1/(val2*val3)
        return result
     

2.动态规划，每一步都是相邻最近的格子的和。 

代码如下

class Solution:
    # @return an integer
    def uniquePaths(self, m, n):
        dp=[[0 for index in range(n)] for index in range(m)]
        for row in range(m):
            dp[row][0]=1
        for col in range(n):
            dp[0][col]=1
        for row in range(1,m):
            for col in range(1,n):
                dp[row][col]=dp[row-1][col]+dp[row][col-1]
        return dp[m-1][n-1]
        

62. Unique Path Leetcode Python

原文：http://blog.csdn.net/hyperbolechi/article/details/43305383