题意:中文题,
思路:线段树的节点更新,储存区间的最大值
#include <iostream> #include <cstdio> #include <cstring> #include <algorithm> using namespace std; const int MAXN = 20010; int tree[MAXN<<1+10]; void build_tree(int l,int r,int root){ if (l == r){ scanf("%d",&tree[root]); return; } int m = (l+r) >> 1; build_tree(l,m,root<<1); build_tree(m+1,r,root<<1|1); tree[root] = max(tree[root<<1],tree[root<<1|1]); } void update(int pos,int date,int l,int r,int root){ if (l == r){ tree[root] = date; return; } int m = (l+r) >> 1; if (pos <= m) update(pos,date,l,m,root<<1); else update(pos,date,m+1,r,root<<1|1); tree[root] = max(tree[root<<1],tree[root<<1|1]); } int query(int L,int R,int l,int r,int root){ int sum = -11111111; if (L <= l && r <= R) return tree[root]; int m = (l+r) >> 1; if (L <= m) sum = max(sum,query(L,R,l,m,root<<1)); if (R > m) sum = max(sum,query(L,R,m+1,r,root<<1|1)); return sum; } int main(){ int num,que; char op; int a,b; while (scanf("%d%d",&num,&que) != EOF){ build_tree(1,num,1); for (int i = 0; i < que; i++){ scanf("%*c%c %d %d",&op,&a,&b); if (op == ‘U‘) update(a,b,1,num,1); else printf("%d\n",query(a,b,1,num,1)); } } return 0; }
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原文:http://blog.csdn.net/u011345136/article/details/20557105