题目链接:https://oj.leetcode.com/problems/binary-tree-inorder-traversal/
题目:
Given a binary tree, return the inorder traversal of its nodes‘ values.
For example:
Given binary tree {1,#,2,3}
,
1 2 / 3
return [1,3,2]
.
Note: Recursive solution is trivial, could you do it iteratively?
confused what "{1,#,2,3}"
means? >
read more on how binary tree is serialized on OJ.
解题思路:基础的中序遍历
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { private: vector<int> s; public: vector<int> inorderTraversal(TreeNode *root) { inOrder(root); return s; } void inOrder(TreeNode *root) { if (root == NULL) return; inOrder(root->left); s.push_back(root->val); inOrder(root->right); } };
LeetCode-Binary Tree Inorder Traversal
原文:http://blog.csdn.net/vanish_dust/article/details/43412093