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Lintcode: Compare Strings

时间:2015-02-05 07:02:06      阅读:261      评论:0      收藏:0      [点我收藏+]
Compare two strings A and B, determine whether A contains all of the characters in B.

The characters in string A and B are all Upper Case letters.

Example
For A = "ABCD", B = "ABC", return true.

For A = "ABCD" B = "AABC", return false.

int数组统计字符出现次数

 1 public class Solution {
 2     /**
 3      * @param A : A string includes Upper Case letters
 4      * @param B : A string includes Upper Case letter
 5      * @return :  if string A contains all of the characters in B return true else return false
 6      */
 7     public boolean compareStrings(String A, String B) {
 8         int[] AA = new int[26];
 9         int[] BB = new int[26];
10         for (int i=0; i<A.length(); i++) {
11             AA[A.charAt(i) - ‘A‘]++;
12         }
13         for (int i=0; i<B.length(); i++) {
14             BB[B.charAt(i) - ‘A‘]++;
15             if (BB[B.charAt(i) - ‘A‘] > AA[B.charAt(i) - ‘A‘]) return false;
16         }
17         return true;
18     }
19 }

 

Lintcode: Compare Strings

原文:http://www.cnblogs.com/EdwardLiu/p/4273817.html

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