3 3 0 1 1 0 2 3 1 2 1 0 2 3 1 0 1 1 1 2
2 -1
#include <stdio.h>
#include <string.h>
#include <vector>
#define N 220
using namespace std;
struct Road{
int next;
int dis;
};
vector<Road>City[N];
int CityNum, RoadNum;
int dij[N];
bool vis[N];
void Init(){
memset(vis, 0, sizeof(vis));
for(int i = 0; i <= CityNum; i ++){
City[i].clear();
dij[i] = 0xfffffff;
}
}
void Dijistra(int cur){
dij[cur] = 0;
while(vis[cur] == 0){
vis[cur] = 1;
for(int i = 0; i < City[cur].size(); i ++){
int next = City[cur].at(i).next;
int dis = City[cur].at(i).dis;
if(dij[next] > dij[cur] + dis){
dij[next] = dij[cur] + dis;
}
}
int min = 0xfffffff;
for(int i = 0; i < CityNum; i ++){
if(!vis[i] && min > dij[i]){
min = dij[i];
cur = i;
}
}
}
}
int main()
{
Road nw;
while(scanf("%d%d", &CityNum, &RoadNum) != EOF){
Init();
int start, end, distance;
for(int i = 0; i < RoadNum; i ++){
scanf("%d%d%d", &start, &end, &distance);
nw.next = start;
nw.dis = distance;
City[end].push_back(nw);
nw.next = end;
City[start].push_back(nw);
}
scanf("%d%d", &start, &end);
Dijistra(start);
if(dij[end] == 0xfffffff){
printf("-1\n");
}
else{
printf("%d\n", dij[end]);
}
}
return 0;
}
#include <stdio.h>
#include <algorithm>
#define N 205
using namespace std;
int map[N][N];
int CityNum, RoadNum;
int floyd(int start, int end){
for(int k = 0; k < CityNum; k ++){
for(int i = 0; i < CityNum; i ++){
for(int j = 0; j < CityNum; j ++){
map[i][j] = min(map[i][j], map[i][k] + map[k][j]);
}
}
}
return map[start][end] < 0xfffffff ? map[start][end] : -1;
}
int main()
{
int start, end, len;
while(scanf("%d%d", &CityNum, &RoadNum) != EOF){
for(int i = 0; i < CityNum; i ++){
for(int j = 0; j < CityNum; j ++){
map[i][j] = (i == j ? 0 : 0xfffffff);
}
}
for(int i = 0; i < RoadNum; i ++){
scanf("%d%d%d", &start, &end, &len);
if(len < map[start][end]){ // 注使用邻接矩阵时 需判断重连
map[end][start] = map[start][end] = len; // 无向图
}
}
scanf("%d%d", &start, &end);
int ans = floyd(start, end);
printf("%d\n", ans);
}
return 0;
}
#include <stdio.h>
struct ROAD{
int from;
int to;
int len;
};
ROAD Road[2020];
int CityNum, RoadNum;
int dis[220];
void Bellman_Ford(int start){
for(int i = 0; i < CityNum; i ++){
dis[i] = 0xfffffff;
}
dis[start] = 0;
for(int i = 0; i < CityNum; i ++){
for(int j = 0; j < RoadNum * 2; j ++){
if(dis[Road[j].to] > dis[Road[j].from] + Road[j].len){
dis[Road[j].to] = dis[Road[j].from] + Road[j].len;
}
}
}
}
int main()
{
int start, end;
while(scanf("%d%d", &CityNum, &RoadNum) != EOF){
for(int i = 0; i < RoadNum; i ++){
scanf("%d%d%d", &Road[i].from, &Road[i].to, &Road[i].len);
Road[RoadNum + i].from = Road[i].to;
Road[RoadNum + i].to = Road[i].from;
Road[RoadNum + i].len = Road[i].len;
}
scanf("%d%d", &start, &end);
Bellman_Ford(start);
if(dis[end] == 0xfffffff){
printf("-1\n");
}
else{
printf("%d\n", dis[end]);
}
}
return 0;
}#include <stdio.h>
#include <string.h>
#include <queue>
#define N 220
using namespace std;
int CityNum, RoadNum;
int map[N][N], dis[N];
bool vis[N];
void Init(){
memset(vis, 0, sizeof(vis));
for(int i = 0; i < CityNum; i ++){
dis[i] = 0xfffffff;
for(int j = 0; j < CityNum; j ++){
map[i][j] = 0xfffffff;
}
}
}
void SPFA(int start){
queue<int>q;
q.push(start);
dis[start] = 0;
while(!q.empty()){
int cur = q.front();
q.pop();
vis[cur] = 0;
for(int i = 0; i < CityNum; i ++){
if(dis[i] > map[cur][i] + dis[cur]){
dis[i] = map[cur][i] + dis[cur];
if(!vis[i]){
q.push(i);
vis[i] = 1;
}
}
}
}
}
int main()
{
int start, end, len;
while(scanf("%d%d", &CityNum, & RoadNum) != EOF){
Init();
for(int i = 0; i < RoadNum; i ++){
scanf("%d%d%d", &start, &end, &len);
if(map[start][end] > len){
map[start][end] = map[end][start] = len;
}
}
scanf("%d%d", &start, &end);
SPFA(start);
if(dis[end] == 0xfffffff){
printf("-1\n");
}
else{
printf("%d\n", dis[end]);
}
}
return 0;
}hduoj-1874 畅通工程续(Dijistra + Floyd + Bellman_Ford + SPFA),布布扣,bubuko.com
hduoj-1874 畅通工程续(Dijistra + Floyd + Bellman_Ford + SPFA)
原文:http://blog.csdn.net/tbl_123/article/details/20646921