P1103 - 多项式输出

  1 program p1103;
  2 
  3 var n,i:integer;
  4 
  5     st,s1,s2:ansistring;
  6 
  7     a:array[0..10000]of integer;
  8 
  9     flag:boolean;
 10 
 11 procedure init;
 12 
 13 begin
 14 
 15  flag:=true;
 16 
 17    readln(n);st:=‘‘;
 18 
 19   for i:=n+1 downto 1 do
 20 
 21    begin
 22 
 23     read(a[i]);
 24 
 25     if (a[i]<>0)and flag then flag:=false;
 26 
 27    end;
 28 
 29   if flag then begin write(‘0‘);halt;end;
 30 
 31 end;
 32 
 33 begin
 34 
 35     init;
 36 
 37   for i:=n+1 downto 2 do
 38 
 39    begin
 40 
 41     if a[i]=0 then begin dec(n);continue;end;
 42 
 43       if a[n+1]<0 then st:=st+‘-‘;
 44 
 45      if i<>n+1
 46 
 47       then if a[i]<0
 48 
 49        then st:=st+‘-‘
 50 
 51        else if a[i]>0
 52 
 53        then st:=st+‘+‘;
 54 
 55          a[i]:=abs(a[i]);
 56 
 57      if (a[i]<>1)
 58 
 59       then begin
 60 
 61              str(a[i],s1);
 62 
 63              st:=st+s1;
 64 
 65            end;
 66 
 67       str(i-1,s2);
 68 
 69       st:=st+‘x‘;
 70 
 71        if i-1>1 then
 72 
 73         begin
 74 
 75           st:=st+‘^‘;
 76 
 77            st:=st+s2;
 78 
 79            end;
 80 
 81   end;
 82 
 83   if a[1]<>0 then
 84 
 85    begin
 86 
 87    if (a[1]>0)and(st<>‘‘) then st:=st+‘+‘;
 88 
 89   str(a[1],s1);
 90 
 91   st:=st+s1;
 92 
 93   end;
 94 
 95   writeln(st);
 96 
 97 readln;
 98 
 99 readln;
100 
101 end.