c# 穷举

//穷举
 int m=0;
                for (int i = 1; i <=200/15; i++)
                {
                    for (int j = 1; j <=200/3 ; j++)
                    {
                        for (int k = 1; k < 200/2; k++)
                        {
                            if (15*i+3*j+2*k==200)
                            {
                                Console.WriteLine(i+"副拍子，" + j + "个球，"+k+"瓶水；");
                                m++;
                            }
                        }
                    }
                }
                Console.WriteLine("总共有"+m+"种可能");

                Console.ReadKey();

c# 穷举

原文：http://www.cnblogs.com/lovesy2413/p/4310590.html