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LeetCode Search Insert Position

时间:2015-03-06 17:09:47      阅读:238      评论:0      收藏:0      [点我收藏+]

1.题目

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You may assume no duplicates in the array.

Here are few examples.
[1,3,5,6], 5 → 2
[1,3,5,6], 2 → 1
[1,3,5,6], 7 → 4
[1,3,5,6], 0 → 0


2.解决方案


class Solution {
public:
    int searchInsert(int A[], int n, int target) {
        for(int i = 0; i < n; i++){
            if(A[i] == target){
                return i;
            }else if((i + 1) < n && A[i] < target && A[i+1] > target){
                return i + 1;
            }
            if(i == n - 1 && A[i] < target){
                return n;
            }
            if(A[0] > target){
                return 0;
            }
        }
        
        return 0;
    }
};

思路:简单数组题目,情况比较多,要仔细考虑。

http://www.waitingfy.com/archives/1598

LeetCode Search Insert Position

原文:http://blog.csdn.net/fox64194167/article/details/44101315

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