HDOJ1002 A+B Problem II

HDOJ1002 A+B Problem II
Wrong Answer.
代码如下：

#include<iostream>

using namespace std;


int main()
{
    int n;
    while(cin>>n &&n)
    {
        int *a = new int[n];
        int sumRun=0,sumStop=0,sumTotal=0;
        int i=0;
        a[0]=0;
        for (i=1;i<=n;i++)
        {
            cin>>a[i];
            if (a[i]>a[i-1]) {
                sumRun = sumRun + ((a[i]-a[i-1])*6);
            }
            else if (a[i]<a[i-1]){
                sumRun = sumRun + ((a[i-1]-a[i])*4);
            }
            else{
                sumRun = sumRun + 0;
            }
        }
        sumStop = n*5;
        sumTotal = sumRun + sumStop;
        cout<<sumTotal<<endl;
    }
    return 0;
}

HDOJ1002 A+B Problem II

原文：http://www.cnblogs.com/wudongyang/p/4333770.html