首页 > 其他 > 详细

3Sum Closest

时间:2015-03-13 18:23:19      阅读:285      评论:0      收藏:0      [点我收藏+]

3Sum Closest

问题:

Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.

思路:

  典型的双指针问题

我的代码:

技术分享
public class Solution {
    public int threeSumClosest(int[] num, int target) {
        int min = Integer.MAX_VALUE;
        if(num == null || num.length < 3)   return min;
        int res = num[0] + num[1] + num[2];
        Arrays.sort(num);
        for(int i = 0; i < num.length - 2; i++)
        {
            int val = num[i];
            int left = i + 1;
            int right = num.length - 1;
            while(left < right)
            {
                int sum = val + num[left] + num[right];
                int gap = Math.abs(target - sum);
                if(min > gap)
                {
                    min = gap;
                    res = sum;
                }
                if(target == sum)
                {
                    return target;
                }
                else if(target > sum)
                {
                    left++;
                }
                else
                {
                    right--;
                }
            }
        }
        return res;
        
    }
}
View Code

 

3Sum Closest

原文:http://www.cnblogs.com/sunshisonghit/p/4335386.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!