LeetCode 192：Reverse Bits

Reverse bits of a given 32 bits unsigned integer.

For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000).

Follow up: If this function is called many times, how would you optimize it?

这个问题就是一个数字移位和赋值的问题，每次取出源操作数的最低位赋给目标操作数，并且源操作数右移一位，目标操作数左移一位。

class Solution {
public:
   uint32_t reverseBits(uint32_t n) 
	{
		uint32_t iRet = 0;
		uint32_t iRes = n;
	
		for(int i = 0; i != 32; ++i)
		{
		    iRet <<= 1;
		    iRet = iRet | iRes & 1;
		    iRes >>= 1;
		}
		return iRet;
	}
};

　　学习了c++的移位运算，c++还是弱的不行，慢慢学，不放弃，总会有改变的！！！

LeetCode 192：Reverse Bits

原文：http://www.cnblogs.com/bestwangjie/p/4338429.html