UP
/UP
and
DOWN
/DOWN
.
The
UP
/UP
tag
capitalizes all letters inside its body (between an open tag and a close one), and
DOWN
/DOWN
makes
all inside the body letters lowercase. You are given the text consisting of latin letters and tags. Your task is to write the text right as it will be shown in the Bernet Explorer browser window. Tags in the text are arranged correctly, i.e. they form correct
bracket sequence. If a letter lays inside several tags, its case is defined by the most inner tag.
sample input |
sample output |
Thi<UP>sIs<DOWN>EaSY</DOWN>Pr<UP>O</UP>ble</UP>m |
ThiSISeasyPROBLEm |
| Online Contester Team ? 2002 - 2010. All rights reserved. |
思路:栈的应用,具体看代码;
AC代码:
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <stack>
using namespace std;
char str[1005];
int main() {
while(gets(str) != NULL) {
stack<int> s;
int len = strlen(str);
for(int i = 0; i < len; i++) {
if(str[i] == '<') {
if(str[i+1] == 'U') { s.push(1); i += 3; }
else if(str[i+1] == 'D') { s.push(2); i += 5; }
else if(str[i+1] == '/') {
s.pop();
if(str[i+2] == 'U') i += 4;
else if(str[i+2] == 'D') i += 6;
}
}
else if(s.empty()) {
printf("%c", str[i]);
}
else if(s.top() == 1) {
if(str[i] >= 'a' && str[i] <= 'z') printf("%c", str[i]-32);
else printf("%c", str[i]);
}
else if(s.top() == 2) {
if(str[i] >= 'A' && str[i] <= 'Z') printf("%c", str[i]+32);
else printf("%c", str[i]);
}
}
printf("\n");
}
return 0;
}
原文:http://blog.csdn.net/u014355480/article/details/44275595