Given a linked list, determine if it has a cycle in it.
Follow up:
Can you solve it without using extra space?
思路:1.两个指针,一个走1步,一个走2步,如果相遇则有环
注意: 在使用p->next时,一定要判断p是否为空。使用p->next->next时,检查p->next是否为空
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: bool hasCycle(ListNode *head) { ListNode *p1 = head; ListNode *p2 = head; while(p1 && p2 && p2->next){ p1=p1->next; p2=p2->next->next; if(p1==p2) return true; } return false; } };
原文:http://www.cnblogs.com/renrenbinbin/p/4340229.html