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hdu 2117:Just a Numble(水题,模拟除法运算)

时间:2014-03-11 04:40:05      阅读:532      评论:0      收藏:0      [点我收藏+]

Just a Numble

Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 2107    Accepted Submission(s): 987


Problem Description
Now give you two integers n m, you just tell me the m-th number after radix point in 1/n,for example n=4,the first numble after point is 2,the second is 5,and all 0 followed
 

 

Input
Each line of input will contain a pair of integers for n and m(1<=n<=10^7,1<=m<=10^5)
 

 

Output
For each line of input, your program should print a numble on a line,according to the above rules
 

 

Sample Input
4 2
5 7
123 123
 

 

Sample Output
5
0
8
 

 

Author
YBB
 

 

Source
 

 

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  水题,但也要动动脑子。
  模拟除法的运算。输入两个数n和m,求出1/n的小数点后的第m位数。
  代码:
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 1 #include <iostream>
 2 
 3 using namespace std;
 4 int main()
 5 {
 6     int n,m;
 7     while(cin>>n>>m){
 8         if(n==1){
 9             cout<<0<<endl;
10             continue;
11         }
12         int num = 10;
13         int d = 0;
14         int dn = 0;
15         while(d!=m){
16             dn = num/n;
17             num = num%n;
18             num*=10;
19             ++d;
20         }
21         cout<<dn<<endl;
22     }
23     return 0;
24 }
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Freecode : www.cnblogs.com/yym2013

hdu 2117:Just a Numble(水题,模拟除法运算),布布扣,bubuko.com

hdu 2117:Just a Numble(水题,模拟除法运算)

原文:http://www.cnblogs.com/yym2013/p/3591627.html

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