题目:
0 0 0 1 0 1 1 0
1.00 1.41
题目分析:
简单题。
代码如下:
/*
* g.cpp
*
* Created on: 2015年3月20日
* Author: Administrator
hdu 2001
*/
#include <iostream>
#include <cstdio>
#include <cmath>
struct PPoint{//结构体尽量不要定义成Point这种,容易和C/C++本身中的变量同名
double x;
double y;
PPoint(double _x = 0,double _y = 0):x(_x),y(_y){
}
PPoint operator - (const PPoint& op2) const{
return PPoint(x - op2.x,y - op2.y);
}
double operator^(const PPoint &op2)const{
return x*op2.y - y*op2.x;
}
};
inline double sqr(const double &x){
return x*x;
}
inline double dis2(const PPoint &p0,const PPoint &p1){
return sqr(p0.x - p1.x) + sqr(p0.y - p1.y);
}
inline double dis(const PPoint& p0,const PPoint& p1){
return sqrt(dis2(p0,p1));
}
int main(){
PPoint p1,p2;
while(scanf("%lf %lf %lf %lf",&p1.x,&p1.y,&p2.x,&p2.y)!=EOF){
printf("%.2lf\n",dis(p1,p2));
}
return 0;
}
(hdu 简单题 128道)hdu 2001 计算两点间的距离
原文:http://blog.csdn.net/hjd_love_zzt/article/details/44537677