首页 > 其他 > 详细

leetcode------Convert Sorted Array to Binary Search Tree

时间:2015-03-24 22:41:57      阅读:284      评论:0      收藏:0      [点我收藏+]
标题: Convert Sorted Array to Binary Search Tree
通过率: 33.8%
难度: 中等

Given an array where elements are sorted in ascending order, convert it to a height balanced BST.

给定的数组是递增的,那么平衡的二叉树一定是从中间开始,左树递归,右树右递归。看代码

 1 /**
 2  * Definition for binary tree
 3  * public class TreeNode {
 4  *     int val;
 5  *     TreeNode left;
 6  *     TreeNode right;
 7  *     TreeNode(int x) { val = x; }
 8  * }
 9  */
10 public class Solution {
11     public TreeNode sortedArrayToBST(int[] num) {
12         return buildTree(num,0,num.length-1);
13     }
14     public TreeNode buildTree(int[] num,int left,int right){
15         if(left>right)return null;
16         int mid=(left+right)/2;
17         TreeNode root=new TreeNode(num[mid]);
18         root.left=buildTree(num,left,mid-1);
19         root.right=buildTree(num,mid+1,right);
20         return root;
21     }
22 }

 

leetcode------Convert Sorted Array to Binary Search Tree

原文:http://www.cnblogs.com/pkuYang/p/4363965.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!