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Min Stack

时间:2015-03-26 20:52:49      阅读:108      评论:0      收藏:0      [点我收藏+]

问题来源:https://leetcode.com/problems/min-stack/

import java.util.Iterator;
import java.util.Stack;

/**
 * 
 * <p>
 * ClassName MinStack
 * </p>
 * <p>
 * Description Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.
 * 
 * push(x) -- Push element x onto stack. pop() -- Removes the element on top of the stack. top() -- Get the top element. getMin()
 * -- Retrieve the minimum element in the stack.
 * </p>
 * 
 * @author TKPad wangx89@126.com
 *         <p>
 *         Date 2015年3月26日 下午6:12:45
 *         </p>
 * @version V1.0.0
 *
 */
public class MinStack {
    Stack<Integer> stack = new Stack<Integer>();
    int minValue = Integer.MAX_VALUE;

    public void push(int x) {
        if (x < minValue) {
            minValue = x;
        }
        stack.push(x);
    }

    public void pop() {
        if (!stack.isEmpty())
            stack.pop();
    }

    public int top() {
        if (!stack.isEmpty())
            return stack.peek();
        return -1;
    }

    public int getMin() {
        if (stack.contains(minValue)) {
            return minValue;
        } else {
            minValue = stack.peek();
            Iterator<Integer> iterator = stack.iterator();
            while (iterator.hasNext()) {
                Integer next = iterator.next();
                if (next < minValue) {
                    minValue = next;
                }
            }
            return minValue;
        }

    }

    public static void main(String[] args) {
        MinStack minStack = new MinStack();
        minStack.push(2);
        minStack.push(0);
        minStack.push(3);
        minStack.push(0);
        System.out.println(minStack.getMin());
        minStack.pop();
        System.out.println(minStack.getMin());
        minStack.pop();
        System.out.println(minStack.getMin());
        minStack.pop();
        System.out.println(minStack.getMin());

    }
}

Min Stack

原文:http://blog.csdn.net/shijiebei2009/article/details/44654941

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