Given two integers n and k, return all possible combinations of k numbers out of 1 ... n.
For example,
If n = 4 and k = 2, a solution is:
[ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ]回溯算法,实现代码:
class Solution {
public:
vector<vector<int> > combine(int n, int k) {
vector<vector<int>> res;
if(n<1||k<1||n<k)
return res;
vector<int> temp;
collect(n,k,0,temp,res);
return res;
}
void collect(int n,int k,int i,vector<int> &temp,vector<vector<int>> &res)
{
if(temp.size()==k)
{
res.push_back(temp);
return;
}
for(;i<n;i++)
{
temp.push_back(i+1);
collect(n,k,i+1,temp,res);
temp.pop_back();
}
}
};
原文:http://blog.csdn.net/wolongdede/article/details/44656685