Given two integers n and k, return all possible combinations of k numbers out of 1 ... n.
For example,
If n = 4 and k = 2, a solution is:
[ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ]回溯算法,实现代码:
class Solution { public: vector<vector<int> > combine(int n, int k) { vector<vector<int>> res; if(n<1||k<1||n<k) return res; vector<int> temp; collect(n,k,0,temp,res); return res; } void collect(int n,int k,int i,vector<int> &temp,vector<vector<int>> &res) { if(temp.size()==k) { res.push_back(temp); return; } for(;i<n;i++) { temp.push_back(i+1); collect(n,k,i+1,temp,res); temp.pop_back(); } } };
原文:http://blog.csdn.net/wolongdede/article/details/44656685