3 3 1 2 1 1 3 2 2 3 4 1 3 2 3 2 0 100
3 ?

//考查知识点:克鲁斯卡尔算法
#include<stdio.h>
#include<string.h>
#include<algorithm>
using namespace std;
struct node{
int sta,end,wei;
}s[110];
int n,m;
int father[110];
int cmp(node x,node y)
{
return x.wei<y.wei;
}
int find(int x)
{
int r=x;
while(r!=father[r])
r=father[r];
int j=x;
while(j!=r)
{
int k=father[j];
father[j]=r;
j=k;
}
return r;
}
//int find(int x)
//{
// return x==father[x]?x:find(father[x]);
//}
void kruskal()
{
int i,j;
int count=1;
int sum=0;
for(i=1;i<=n;++i)
{
int fa=find(s[i].sta);
int fb=find(s[i].end);
if(fa!=fb)
{
father[fa]=fb;
sum+=s[i].wei;
count++;
}
}
if(count==m)
printf("%d\n",sum);
else
printf("?\n");
}
int main()
{
int i,j;
while(~scanf("%d%d",&n,&m),n)
{
for(i=1;i<=m;++i)
father[i]=i;
for(i=1;i<=n;++i)
{
scanf("%d%d%d",&s[i].sta,&s[i].end,&s[i].wei);
}
sort(s+1,s+n+1,cmp);
kruskal();
}
return 0;
} 原文:http://blog.csdn.net/ice_alone/article/details/44700793