NYOJ2 括号配对问题

原题链接

#include <stdio.h>
char buf[10001];

int main(){
	int t;
	char *p, ch;
	scanf("%d\n", &t);
	while(t--){
		buf[0] = getchar();
		p = buf + 1;
		while((ch = getchar()) != ‘\n‘){
			if(ch - 1 == *(p - 1) || ch - 2 == *(p - 1))
				--p;
			else *p++ = ch;
		}
		printf(p == buf? "Yes\n": "No\n");
	}
	return 0;
}

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NYOJ2 括号配对问题

原文：http://blog.csdn.net/chang_mu/article/details/20989635