【CF】C. Glass Carving（二分 + 树状数组 + 优先队列 + 数组计数）

这题简直蛋疼死。。。。。

A了一下午

#include<cstdio>
#include<queue>
#include<cstring>
#include<algorithm>
using namespace std;
typedef long long LL;
const int maxn = 200005;
int h,w,n;
int C1[maxn],C2[maxn];
int vis1[maxn] = {0},vis2[maxn] = {0};
priority_queue<int,vector<int>,less<int> >q1;
priority_queue<int,vector<int>,less<int> >q2;
int lowbit(int x){
    return x & -x;
}
int sum(int C[],int x){
    int ret = 0;
    while(x > 0){
        ret += C[x];
        x -= lowbit(x);
    }
    return ret;
}
void add(int x,int d,int n,int C[]){
    while(x <= n){
        C[x] += d;
        x += lowbit(x);
    }
}
int main(){
    memset(C1,0,sizeof(C1));
    memset(C2,0,sizeof(C2));
    scanf("%d%d%d",&w,&h,&n);
    int max_width  = w;
    int max_height = h;
    int oh = 0, ow = 0;
    vis1[h] ++; q1.push(h);
    vis2[w] ++; q2.push(w);
    h ++;
    w ++;
    add(1,1,h,C1);  add(h,1,h,C1);
    add(1,1,w,C2);  add(w,1,w,C2);
    for(int i = 0; i < n; i++){
        char str[7];
        int d;
        scanf("%s%d",str,&d);
        d ++;
        if(str[0] == 'H'){
            int l = 1,r = d - 1;
            int e1,e2;
            int v = sum(C1,d);
            while(l < r){
                int mid = (l + r) >> 1;
                int ans = sum(C1,mid);
                if(ans >= v)
                    r = mid;
                else
                    l = mid + 1;
            }
            e1 = l;
            add(d,1,h,C1);
            v = sum(C1,d) + 1;
            l = d + 1;
            r = h;
            while(l < r){
                int mid = (l + r) >> 1;
                int ans = sum(C1,mid);
                if(ans < v)
                    l = mid + 1;
                else
                    r = mid;
            }
            e2 = l;
            int d1 = d - e1,d2 = e2 - d;
            vis1[d1 + d2]--;
            if(!vis1[d1]) q1.push(d1);
            if(!vis1[d2]) q1.push(d2);
            vis1[d1] ++;
            vis1[d2] ++;
            while(!q1.empty()){
                int t = q1.top(); q1.pop();
                if(vis1[t]){
                    max_height = t;
                    q1.push(t);
                    break;
                }
            }
        }
        else if(str[0] == 'V'){
            int l = 1,r = d - 1;
            int e1,e2;
            int v = sum(C2,d);
            while(l < r){
                int mid = (l + r) >> 1;
                int ans = sum(C2,mid);
                if(ans < v)
                    l = mid + 1;
                else
                    r = mid;
            }
            e1 = l;
            add(d,1,w,C2);
            v = sum(C2,d) + 1;
            l = d + 1;
            r = w;
            while(l < r){
                int mid = (l + r) >> 1;
                int ans = sum(C2,mid);
                if(ans < v)
                    l = mid + 1;
                else
                    r = mid;
            }
            e2 = l;
            int d1 = d - e1,d2 = e2 - d;
            vis2[d1 + d2]--;
            if(!vis2[d1]) q2.push(d1);
            if(!vis2[d2]) q2.push(d2);
            vis2[d1] ++;
            vis2[d2] ++;
            while(!q2.empty()){
                int t = q2.top(); q2.pop();
                if(vis2[t]){
                    max_width = t;
                    q2.push(t);
                    break;
                }
            }
        }
        printf("%I64d\n",(LL)max_width * max_height);
    }
    return 0;
}

【CF】C. Glass Carving（二分 + 树状数组 + 优先队列 + 数组计数）

原文：http://blog.csdn.net/u013451221/article/details/44781947