Time Limit: 2000/1000 MS
(Java/Others) Memory Limit: 65536/32768 K
(Java/Others)
Total Submission(s): 10423 Accepted
Submission(s): 4287
1 #include <iostream>
2
3 using namespace std;
4 struct stick{
5 int l,w;
6 }s[5010];
7 int main()
8 {
9 int T;
10 cin>>T;
11 while(T--){
12 int n;
13 cin>>n;
14 for(int i=1;i<=n;i++)
15 cin>>s[i].l>>s[i].w;
16 //对l排序
17 for(int i=1;i<=n-1;i++)
18 for(int j=1;j<=n-i;j++){
19 if(s[j].l>s[j+1].l){
20 int t;
21 t=s[j].l;s[j].l=s[j+1].l;s[j+1].l=t;
22 t=s[j].w;s[j].w=s[j+1].w;s[j+1].w=t;
23 }
24 }
25 int sum=0; //递增序列的个数
26 //对w序列进行筛选
27 while(1){
28 int i;
29 for(i=1;i<=n;i++){ //如果全部为-1,则退出循环
30 if(s[i].w!=-1)
31 break;
32 }
33 if(i>n) break;
34 sum++;
35 int num=0;
36 for(i=1;i<=n;i++){
37 if(num==0 && s[i].w!=-1){
38 num=s[i].w;
39 s[i].w=-1;
40 }
41 else if(s[i].w!=-1 && s[i].w>=num){
42 num=s[i].w;
43 s[i].w=-1;
44 }
45 }
46 }
47 cout<<sum<<endl;
48
49 }
50 return 0;
51 }
Freecode : www.cnblogs.com/yym2013
hdu 1051:Wooden Sticks(水题,贪心),布布扣,bubuko.com
原文:http://www.cnblogs.com/yym2013/p/3594468.html