Given a binary tree, determine if it is height-balanced.
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.
/**
* Definition for binary tree
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public boolean isBalanced(TreeNode root) {
if(root==null)
return true;
if(root.left==null&&root.right==null)
return true;
int len=maxDepth(root.left)-maxDepth(root.right);
if(Math.abs(len)<=1&&isBalanced(root.left)&&isBalanced(root.right))
return true;
return false;
}
public int maxDepth(TreeNode root) {
if(root==null)
return 0;
if(root.left==null&&root.right==null)
return 1;
int num1=maxDepth(root.left),num2=maxDepth(root.right);
int num=(num1>=num2?num1:num2)+1;
return num;
}
}leetcode_110_Balanced Binary Tree
原文:http://blog.csdn.net/mnmlist/article/details/44855909