题目:
Given a sorted linked list, delete all duplicates such that each element appear only once.
For example,
Given 1->1->2, return 1->2.
Given 1->1->2->3->3, return 1->2->3.
解题思路:设置两个指针CurrList和NewList,初始化为同一头指针,CurrList不断向链表尾部扫描,如果当前节点的值不是重复值,就将该节点接到NewList尾部。
代码:
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode *deleteDuplicates(ListNode *head) {
if(head==NULL){
return NULL;
}
int temp=head->val;
ListNode *CurrList=head;
ListNode *NewList=head;
while(CurrList->next){
CurrList=CurrList->next;
if(CurrList->val!=temp){
NewList->next=CurrList;
NewList=NewList->next;
temp=CurrList->val;
}
}
NewList->next=CurrList->next;
return head;
}
};【Leetcode】Remove Duplicates from Sorted List,布布扣,bubuko.com
【Leetcode】Remove Duplicates from Sorted List
原文:http://blog.csdn.net/ussam/article/details/21031175