首页 > 数据库技术 > 详细

杭电 HDU ACM 1397 Goldbach's Conjecture

时间:2015-04-05 11:58:31      阅读:277      评论:0      收藏:0      [点我收藏+]

Goldbach‘s Conjecture

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 4976    Accepted Submission(s): 1901


Problem Description
Goldbach‘s Conjecture: For any even number n greater than or equal to 4, there exists at least one pair of prime numbers p1 and p2 such that n = p1 + p2.
This conjecture has not been proved nor refused yet. No one is sure whether this conjecture actually holds. However, one can find such a pair of prime numbers, if any, for a given even number. The problem here is to write a program that reports the number of all the pairs of prime numbers satisfying the condition in the conjecture for a given even number.

A sequence of even numbers is given as input. Corresponding to each number, the program should output the number of pairs mentioned above. Notice that we are interested in the number of essentially different pairs and therefore you should not count (p1, p2) and (p2, p1) separately as two different pairs.
 

Input
An integer is given in each input line. You may assume that each integer is even, and is greater than or equal to 4 and less than 2^15. The end of the input is indicated by a number 0.
 

Output
Each output line should contain an integer number. No other characters should appear in the output.
 

Sample Input
6 10 12 0
 

Sample Output
1 2 1
 
如果必然能写成两素数和那么先判断第一个数m是否为素数,且n-m也为素数,计时器加1,注意不要重复。
#include<iostream>
#include<cmath>
using namespace std;
int ls[40000];

void A()
{
	int i,j;
	for(int k=0;k<=40000;k++)
		ls[k]=1;
	for( i=2;i<=sqrt(40000);i++)
	{
		if(ls[i])
		{
			for( j=i+i;j<40000;j+=i)
				ls[j]=0;
		}
	}
	
}
int main()
{
	int n;
    A();
	while(cin>>n,n)
	{
		int count=0;
		for(int m=2;m<=n/2;m++)
			if(ls[m]&&ls[n-m])
				count++;
		cout<<count<<endl;
	}
	return 0;
}


杭电 HDU ACM 1397 Goldbach's Conjecture

原文:http://blog.csdn.net/lsgqjh/article/details/44886323

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!