3 3 21 25
None 11 5
zhuyuanchen520 | We have carefully selected several similar problems for you: 4390 4398 4397 4395 4393
ac代码
#include<stdio.h> #include<string.h> #define INF 1<<30 #define max(a,b) (a>b?a:b) #define min(a,b) (a>b?b:a) int a[20]; __int64 mod[20],ans,n,len; void init() { mod[0]=1; for(int i=1;i<20;i++) { mod[i]=mod[i-1]*10; } } void fun() { __int64 temp=n; len=0; memset(a,0,sizeof(a)); while(temp) { a[len++]=temp%10; temp/=10; } } void dfs(int now,int step) { if(step==len) { ans=min(ans,now); return; } for(int i=0;i<=9;i++) { __int64 to,temp=now+mod[step]*i; to=temp; temp*=temp; temp/=mod[step]; temp%=10; if(temp==a[step]) { dfs(to,step+1); } } } int main() { int t; init(); scanf("%d",&t); while(t--) { scanf("%I64d",&n); fun(); ans=INF; dfs(0,0); if(ans==INF) { printf("None\n"); } else printf("%d\n",ans); } }
HDOJ 题目4394 Digital Square(DFS)
原文:http://blog.csdn.net/yu_ch_sh/article/details/44890631