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[LeetCode]Minimum Path Sum

时间:2015-04-06 12:50:42      阅读:216      评论:0      收藏:0      [点我收藏+]
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.


Note: You can only move either down or right at any point in time.
思路1:这是一个简单的动态规划问题,dp[i][j] = grid[i-1][j-1] + min(dp[i-1][j],dp[i][j-1])
代码1:
public class Solution {
    public int minPathSum(int[][] grid) {
        
        int m = grid.length, n = grid[0].length;
        int[][] sums = new int[m][n];
        
        for(int i = 0; i < m; i ++){
            for(int j = 0; j < n; ++j){
                if(i == 0 && j == 0){
                    sums[i][j] = grid[i][j];
                }else if(i == 0 && j != 0){
                    sums[i][j] = grid[i][j] + sums[i][j-1];
                }else if(i !=0 && j == 0){
                    sums[i][j] = grid[i][j] + sums[i-1][j];
                }else {
                    sums[i][j] = Math.min(grid[i][j] + sums[i][j-1],grid[i][j] + sums[i-1][j]);
                }
            }
        }
        return sums[m-1][n-1];
    }
}
思路2:看到网上说可以把空间复杂度优化到O(N)

[LeetCode]Minimum Path Sum

原文:http://blog.csdn.net/youmengjiuzhuiba/article/details/44901135

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