C语言指针理解

#include <stdio.h>
int main(void){
int zippo[4][2] = {{2,4},{6,8},{1,3},{5,7}};
printf("    zippo = %p,    zippo + 1 = %p\n",zippo,zippo +1);
printf("    zippo[0] = %p,    zippo[0] + 1 = %p\n",zippo[0],zippo[0] +1);
printf("    *zippo = %p,    *zippo + 1 = %p\n",*zippo,*zippo +1);
printf("    zippo[0][0] = %d\n",zippo[0][0]);
printf("    **zippo =  %d\n",**zippo);
printf("    *zippo[0] = %d\n",*zippo[0]);
printf("    zippo[2][1] = %d\n",zippo[2][1]);
printf("    *(*(zippo + 2) + 1) = %d\n",*(*(zippo + 2) + 1));
printf("    zippo = %p,&zippo = %p,&zippo[0] = %p,zippo[0] = %p,&zippo[0][0] = %p,zippo[0][0] = %d\n",zippo,&zippo,&zippo[0],zippo[0],&zippo[0][0],zippo[0][0]);

printf("    *(*(zippo + 1) + 2) = %d,zippo[1][2] = %d\n",*(*(zippo + 2) + 1),zippo[1][2]);
printf("    &zippo[0][0] = %p,&zippo[0][1] = %p,&zippo[1][0] = %p,&zippo[1][1] = %p,&zippo[2][0] = %p,&zippo[2][1] = %p,&zippo[3][0] = %p,&zippo[3][1] = %p\n",&zippo[0][0],&zippo[0][1],&zippo[1][0],&zippo[1][1],&zippo[2][0],&zippo[2][1],&zippo[3][0],&zippo[3][1]);
return 0;

}