A+B Coming
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 6464 Accepted Submission(s): 4248
Problem Description
Many classmates said to me that A+B is must needs.
If you can’t AC this problem, you would invite me for night meal. ^_^
Input
Input may contain multiple test cases. Each case contains A and B in one line.
A, B are hexadecimal number.
Input terminates by EOF.
Output
Output A+B in decimal number in one line.
Sample Input
Sample Output
这个题无语……表示以前见过 但是忘了！！
知识一：
将十六进制转换为十进特例：
AB转换为dec；
0xAB
= 0x0A * 16 + 0x0B
= 10 * 16 + 11
= 171
c 输入十六进制和八进制方法：
scanf（“%x %x”，&a，&b）；
scanf（“%o %o”，&a，&b）；
c++ 方法：
cin>>hex>>a>>b;
cin>>oct>>a>>b;
输出与之类似 ，
败了 看来要请吃饭了！
AC：
#include<iostream>
using namespace std;
int main()
{
int a,b;
while(cin>>hex>>a>>b)
cout<<dec<<a+b<<endl;
return 0;
}
杭电 HDU ACM 1720 A+B Coming
原文：http://blog.csdn.net/lsgqjh/article/details/44926311
